How to convert JsonNode to ObjectNode

Question

I have a com.fasterxml JsonNode object with some data. I need to do some manipulation on its data. I googled for answer but didn't got it properly. Can you please suggest me how to manipulate JsonNode data. I have also tried to convert JsonNode to ObjectNode as follows

ObjectNode objectNode = (ObjectNode)filterJson;

but its giving following exception....

java.lang.ClassCastException: com.fasterxml.jackson.databind.node.TextNode cannot be cast to 
com.fasterxml.jackson.databind.node.ObjectNode

please help!!

Chances are you are trying to convert the value of ObjectNode to an objectNode. ObjectNode means {"test":"value"} and you are probably typecasting value node. If you can share the code, may be suggestions can be made on which node you should cast — Optional, Sep 22 '15 at 09:27

score 56 · Answer 1 · edited Sep 21 '17 at 19:01

56

You can convert a JsonNode in an ObjectNode in this simple way:

ObjectNode objectNode = jsonNode.deepCopy();

Available from Jackson 2.0 and tested with Jackson 2.4.0

edited Sep 21 '17 at 19:01

Andrea Bergonzo

3,983
4
19
31

answered Dec 22 '16 at 09:11

Daniele Licitra

1,520
21
45

Mr. Noddy · Accepted Answer · 2016-12-07T15:03:40.210

35

Finally, I got the solution as follows...

JsonNode jsonNode = Json.toJson("Json String");
ObjectNode node = (ObjectNode) new ObjectMapper().readTree(jsonNode.asText());
//perform operations on node
jsonNode = (JsonNode) new ObjectMapper().readTree(node.toString());

or another one as below...

ObjectNode node = (ObjectNode) new ObjectMapper().readTree("Json String")
//perform operations on node
jsonNode = (JsonNode) new ObjectMapper().readTree(node.toString());

but I don't know if this is good approach or not ? If there is any better than above, please let me know. Thank you!

edited Dec 07 '16 at 15:03

answered Sep 23 '15 at 07:22

Mr. Noddy

1,530
2
16
45

4

I think you are supposed to call JsonNode.isObject() to make sure you can cast before casting. – romnempire Apr 24 '19 at 18:42
1

Definitely, it's worth checking the type before. Imagine that incoming String is not an expected JSON value but literally, a number f.ex "737". Then readTree() would convert it into IntNode object which cannot be cast into ObjectNode what will result with ClassCastException. – Macieyo Apr 25 '19 at 10:07
1

I'm facing the similar problem, my string is coming as a number "71" and readTree() method is converting it into IntNode object and it is throwing ClassCastException. How to convert IntNode into ObjectNode in that case? – Rachit Munjal Jan 14 '21 at 11:36
Add the following import for the above to work, import com.fasterxml.jackson.databind.node.ObjectNode; – Anurag Bhalekar Sep 19 '22 at 06:02

score 5 · Answer 3 · answered Jul 30 '19 at 08:35

5

I had this error too although in my case it was a stupid mistake. I accidentally imported org.codehaus.jackson.node.ObjectNode instead of com.fasterxml.jackson.databind.node.ObjectNode. Using the jackson ObjectNode fixed the issuse.

answered Jul 30 '19 at 08:35

dozer

861
1
11
22

score 0 · Answer 4 · answered Jul 03 '22 at 14:00

0

You can covert JsonNode to ObjectNode this way:

JsonNode demoPath = requestParams.at("/Subscription/0");
((ObjectNode) demoPath).put("mylID", "test12");

answered Jul 03 '22 at 14:00

Testilla

602
8
21

score -2 · Answer 5 · edited Jan 04 '18 at 07:08

-2

I try it some times, it will be ok! You only define a Student Class to map the properties. Then you could convert the jsonNode to Student Object.

Student student = objectMapper.convertValue(jsonNode1, Student.class);

I think this will be suitable for your need!

edited Jan 04 '18 at 07:08

31piy

23,323
6
47
67

answered Jan 04 '18 at 06:28

Daejong Lin

25
2

The question is how to convert a JsonNode in a com.fasterxml.jackson.databind.node.ObjectNode, not in a some Object instance – Daniele Licitra Mar 01 '18 at 16:13

How to convert JsonNode to ObjectNode

5 Answers5

Linked