Big decimal Conversion with roundup value

Question

i have a double value Such as

Double doubleValue=0.0001;

trying to print this gave me an output as 1.0E-4

So I tried BigDecimal to value of this as.

BigDecimal.valueOf(doubleValue) which ended up giving output as "0.00010".

can anyone let me know how would I get a round up value as "0.0001".( no end trail of 0 after 1)

possible duplicate of [java decimal String format](http://stackoverflow.com/questions/433958/java-decimal-string-format) — azurefrog, Sep 24 '15 at 04:16

Balwinder Singh · Accepted Answer · 2015-09-24T04:41:49.563

1

You can try code similar to following

Double doubleValue=0.0001;    
DecimalFormat f = new DecimalFormat("##.0000");
String formattedValue = f.format(doubleValue);
BigDecimal bigDecimalValue = new BigDecimal(formattedValue);
bigDecimalValue.stripTrailingZeros();

Hope this helps

edited Sep 24 '15 at 04:41

answered Sep 24 '15 at 04:23

Balwinder Singh

2,272
5
23
34

but in case of input as 0.01 this returns output as 0.0100 – Kumar Sep 24 '15 at 04:31
@Kumar Yes, that true. I thought you were looking to keep till 4 decimal places – Balwinder Singh Sep 24 '15 at 04:39
am sry for not making it clear.... I would need precision max of 4.. and no end trails of 0 for the value. – Kumar Sep 24 '15 at 04:43
@Kumar Have you tried my updated answer? It should do the job -- precision max of 4 and no end trails of 0 for the value – Balwinder Singh Sep 24 '15 at 04:45

Archytekt · Answer 2 · 2015-09-24T05:12:43.577

1

Are you printing with println? You should use printf to format your output.

        Double d = 0.000100;
        System.out.printf("%.4f",d);

The following will print "0.0001"

Hope this helps!

edited Sep 24 '15 at 05:12

answered Sep 24 '15 at 05:05

Archytekt

21
2

Big decimal Conversion with roundup value

2 Answers2