How to replace line number delimiter in grep output

Question

I am doing:

egrep -e "String" -in -A 2 file1.log

I am getting output as

111:some text
112-some text
113-some text

How to replace ^'[0-9]{1,9}-' to ^'[0-9]{1,9}:' for each line number at start of each line in a file? So that it will look like:

111:some text
112:some text
113:some text

Take a look at http://stackoverflow.com/questions/1169927/using-sed-and-grep-to-search-and-replace, hope it helps! — Mattias Lindberg, Sep 24 '15 at 10:37
I tried but not worked. I am looking solution like this egrep -e "String" -in -A 2 file1.log | sed 's/^'[0-9]{1,9}-'/^'[0-9]{1,9}:'/' — ypp, Sep 24 '15 at 10:57

score 1 · Accepted Answer · answered Sep 24 '15 at 11:34

1

Pipe the output into sed. This works here:

grep ... | sed 's/^\([0-9]\+\)-/\1:/'

answered Sep 24 '15 at 11:34

Thor

Thanks a lot thor :) , yes its working but it also deleting group separators '--'. Just as workaround I changed group separators as '==' using this option of grep "--group-separator==" – ypp Sep 24 '15 at 11:48
@ypp: Yes I noticed that and changed the pattern to use the `\+` quantifier instead of `*`. – Thor Sep 24 '15 at 12:30

1 Answers1