I am trying to implement a buffer overflow attack and I need to know the address of my buffer that I am trying to overflow.
The address that is displayed using GDB is different than if I just did this in the code:
Exact code:
#include<stdio.h>
int main() {
char buffer[20];
printf("%p\n", buffer); // 0xbffff320
return 0;
}
However, in gdb if I do:
p &buffer
I get: 0xbffff330
Why is there a difference and will it mess up my buffer overflow attack?
I have ALSR and stack guard disabled.
Thanks.
EDIT 1: Even when I step through gdb and it encounters the print line, I get 0xbffff320 as the address
EDIT 2:
Environment: Ubuntu Linux 9 image running in virtual box on windows 7.
The gdb version: 6.8-debian
Compiled using GCC such as: gcc -g -fno-stack-protector filename.c
execute immediately: ./a.out
address printed: 0xbffff320
Then open in debugger like this: gdb ./a.out
then enter b main
then run
then p &buffer
Then address is 0xbffff330
Edit 3:
This is the gdb log to reproduce behavior:
$ gdb ./a.out
b main
run
p &buffer /* address here is different than what is shown if I run executable */
step through program to printf statement /* address here is same as p &buffer but different than what is printed when program is ran */