Qt child qmainwindow disappear at pop out

Question

I have one button on MainWindow to show another QMainWindow.

void MainWindow::viewSecondWindow()
{
    QMainWindow w = new QMainWindow(this);
    w.show();
}

The code got compiled well and ran succesfully. However if I click on the button , the second window does pop out but it automatically closes.

Edit :

For the future people who face similiar situation, please refer to this. Why use pointers?

Did you mean QMainWindow *w = new QMainWindow(this); actually? — demonplus, Sep 25 '15 at 04:47
hi @demonplus, that just solved my problem. Thank you so much. I'm very new to c++. If you could write ur answer below I will mark it as accepted. Thanks again. Have a good day. — HohoHaha, Sep 25 '15 at 04:59

score 0 · Answer 1 · answered Sep 25 '15 at 04:42

0

you can use QDialog in place of Mainwindow

answered Sep 25 '15 at 04:42

shengfu zou

How will QDialog help him if he needs to create QMainWindow ? – demonplus Sep 25 '15 at 04:48

score 0 · Accepted Answer · answered Sep 25 '15 at 05:06

0

You need to use the following instead:

QMainWindow *w = new QMainWindow(this);

Because otherwise w will be destroyed immediately after show().

answered Sep 25 '15 at 05:06

demonplus

2 Answers2