Regex with all special symbols

Question

I need regex that will allow only Latin characters, digits and all other symbols(but not whitespace)

thanks!

UPDATE:

private boolean loginPassHasCorrectSymbols(String input){
        if (input.matches("[A-Za-z0-9\!\"\#\$\%\&\'\(\)\*\+\,\-\.\/\:\;\<\>\=\?\@\[\]\{\}\\\^\_\`\~]+$")){
            return true;
        }
        return false;
    }

When you say "special symbols", do you mean all of the [basic Latin](https://en.wikipedia.org/wiki/List_of_Unicode_characters#Latin_script) characters that aren't alphanumeric characters? — BrockLee, Sep 25 '15 at 18:22
all symbols that can be typed from keyboard, but i think you are right ) — Stan Malcolm, Sep 25 '15 at 18:28
If you need to protect just Cyrillic letters, why not use [`(?U)^[^\\s\\p{IsCyrillic}]*$`](http://ideone.com/NieW6x)? Try `input.matches("(?U)[^\\s\\p{IsCyrillic}]*")`. — Wiktor Stribiżew, Sep 25 '15 at 18:50
@stribizhev Syntax error in regexp pattern near index 3: (?U)[^\s\p{IsCyrillic}]* — Stan Malcolm, Sep 25 '15 at 18:59
Were you also hoping to capture whitespace also? The regex I gave you includes almost everything except for whitespace. — BrockLee, Sep 25 '15 at 19:07

BrockLee · Accepted Answer · 2015-09-25T19:28:09.113

6

I hope I got them all.

"[A-Za-z0-9\!\"\#\$\%\&\'\(\)\*\+\,\-\.\/\:\;\<\>\=\?\@\[\]\{\}\\\\\^\_\`\~]+$"

Edit: I forgot that in Java, the regexes are also strings, so you need to actually escape each \ given in the string using another \. I hope I didn't miss any now.

"[A-Za-z0-9\\!\\\"\\#\\$\\%\\&\\'\\(\\)\\*\\+\\,\\-\\.\\/\\:\\;\\<\\>\\=\\?\\@\\[\\]\\{\\}\\\\\\^\\_\\`\\~]+$"

edited Sep 25 '15 at 19:28

answered Sep 25 '15 at 18:33

BrockLee

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@LeoCHan: You know Python re better I guess, right? You do not need `$`. – Wiktor Stribiżew Sep 25 '15 at 18:56
@stribizhev I imagine I'm fairly decent in both Java and Python. Java was my first after all :) But in the original post, the OP had a `$` at the end of his original regex which made me assume he wanted a `$` to mark the end of a line. – BrockLee Sep 25 '15 at 18:58
@LudoBagman I just added more backslashes hoping I escaped everything correctly. – BrockLee Sep 25 '15 at 19:04
without symbol " here \\!\\" - it works ) how can I add this symbol? – Stan Malcolm Sep 25 '15 at 19:15
1

Just a shot in the dark, but check if adding more backslashes will work, making it `\\!\\\"`. So for the `\\\"`, you have 2 backslashes to get one `\\` and another backslash to get `"`. If it works, tell me so I can update my answer please. – BrockLee Sep 25 '15 at 19:23
The regex is incorrect – Jorgesys Feb 22 '23 at 17:26

score 2 · Answer 2 · answered Sep 25 '15 at 18:22

2

How about everything not a whitespace?

"^\S+$"

answered Sep 25 '15 at 18:22

Shawn Mehan

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nope ) cos, i need in such case protect cyrillic symbols ) – Stan Malcolm Sep 25 '15 at 18:26
Hmm, Cyrillic wasn't part of the requirement as I grokked it. I have no experience with that but knowledge thereof :). You might get something out of [this](http://stackoverflow.com/questions/1716609/how-to-match-cyrillic-characters-with-a-regular-expression) but I don't even know how to test it myself .... Good luck. – Shawn Mehan Sep 25 '15 at 19:07

score 0 · Answer 3 · answered Jan 28 '19 at 07:28

I did this and it works for me .

Either you can block whitespace by mentioning it on Edittext, or you can block on editetext.addtextChangeListner too by pragmatically .

1>

android:digits="0,1,2,3,4,5,6,7,8,9,*,qwertzuiopasdfghjklyxcvbnm,_,-"

2>

etNewPassword.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {

                if (etNewPassword.getText().toString().contains(" ")) {
                    etNewPassword.setText(etNewPassword.getText().toString().replace(" ", ""));
                    int iLength = etNewPassword.getText().toString().length();
                    etNewPassword.setSelection(iLength);
                }
            }

            @Override
            public void afterTextChanged(Editable s) {

            }
        });

Let me know if any concern.

score 0 · Answer 4 · answered Jun 14 '21 at 10:27

0

For find any symbol except whitespace, you can use this code. I hope you find it useful

public static boolean hasAnySymbolExceptWhitespace(String string){
    return Pattern.matches("(?=.*[^a-zA-Z0-9] ).*", string);
}

answered Jun 14 '21 at 10:27

fvaldivia

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score 0 · Answer 5 · answered Jan 24 '22 at 13:58

Smooth Kotlin solution which allows English letters with some default symbols. Cyrillic or any other language symbols won't be allowed.

//Allows english with usual symbols 
private fun hasNonAllowedSymbols(input: String) : Boolean {
    val regex = "[a-zA-Z0-9\\s-#,/~`'!@$%^&*()_+={}|;<>.?:\"\\[\\]\\\\]*"
    val pattern = Pattern.compile(regex)
    return !pattern.matcher(input).matches()
}

Regex with all special symbols

5 Answers5

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