Run php function on button click

Question

I want to run a php function on button click. for eg :

<input type="button" name="test" id="test" value="RUN"  onclick="<?php echo testfun(); ?>" /><br/>

<?php

function testfun()
{
   echo "Your test function on button click is working";
}

?>

My question is that when I do this I don't get the expected output I was looking for. Please give me the best solution for this to run a php function on button click whether it is a simple button or submit.

You can`t do this, php is a scripting language. If you want click events try Javascript — ka_lin, Sep 28 '15 at 13:34

score 24 · Accepted Answer · answered Sep 28 '15 at 14:27

I tried the code of William, Thanks brother.

but it's not working as a simple button I have to add form with method="post". Also I have to write submit instead of button.

here is my code below..

<form method="post">
    <input type="submit" name="test" id="test" value="RUN" /><br/>
</form>

<?php

function testfun()
{
   echo "Your test function on button click is working";
}

if(array_key_exists('test',$_POST)){
   testfun();
}

?>

score 7 · Answer 2 · answered Sep 28 '15 at 13:39

7

Do this:

<input type="button" name="test" id="test" value="RUN" /><br/>

<?php

function testfun()
{
   echo "Your test function on button click is working";
}
if(array_key_exists('test',$_POST)){
   testfun();
}
?>

answered Sep 28 '15 at 13:39

William Madede

727
4
8

will it work, without wrapped by a `form` tag which has `method ="POST"` attribute? – marmeladze Sep 28 '15 at 13:50

score 2 · Answer 3 · answered Sep 28 '15 at 14:57

2

<a href="home.php?click=1" class="btn">Click me</a>
<?php 
  if($_GET['click']){
    doSomething();
  }
?>

But is better to use JS and with ajax to call function!

answered Sep 28 '15 at 14:57

Ivan Abadzhiev

69
5

score 2 · Answer 4 · edited Apr 17 '19 at 05:56

2

You can use isset().

<form method="post">
    <input type="submit" name="test" id="test" value="RUN" />

</form>

<?php

function testfun()
{
   echo "Your test function on button click is working";
}

if(isset($_POST('submit')))
{
   testfun();
}

?>

edited Apr 17 '19 at 05:56

Laurenz Albe

209,280
17
206
263

answered Apr 17 '19 at 05:22

deepak mishra

310
2
13

score 1 · Answer 5 · answered Sep 28 '15 at 13:49

You are trying to call a javascript function. If you want to call a PHP function, you have to use for example a form:

    <form action="action_page.php">
       First name:<br>
       <input type="text" name="firstname" value="Mickey">
       <br>
       Last name:<br>
       <input type="text" name="lastname" value="Mouse">
       <br><br>
       <input type="submit" value="Submit">
     </form>

(Original Code from: http://www.w3schools.com/html/html_forms.asp)

So if you want do do a asynchron call, you could use 'Ajax' - and yeah, that's the Javascript-Way. But I think, that my code example is enough for this time :)

score -1 · Answer 6 · edited Aug 16 '17 at 15:53

-1

No Problem You can use onClick() function easily without using any other interference of language,

<?php
echo '<br><Button onclick="document.getElementById(';?>'modal-wrapper2'<?php echo ').style.display=';?>'block'<?php echo '" name="comment" style="width:100px; color: white;background-color: black;border-radius: 10px; padding: 4px;">Show</button>';
?>

edited Aug 16 '17 at 15:53

Dávid Pásztor

51,403
9
85
116

answered Aug 16 '17 at 14:15

Rahul Gite

1

Hello, the button shows... but I don't get the application so the solution for the question. Thank you if you add it. – Robert Aug 22 '17 at 05:28

Run php function on button click

6 Answers6

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