How 30%4 output is 2 but if I write 30*4/100 output is 1

Question

System.out.println("30%4 = " + 30%4);
System.out.println("33%4 = " + 33%4);

System.out.println("30*4/100 = " + 30*4/100);
System.out.println("33*4/100 = " + 33*4/100);

My Question is why 2 not 1 in 30%4 case. Can anybody explain me in details. Thanks in Advance

Those are basic modulo and division arithmetics, I would google it instead. — Tamir Vered, Sep 30 '15 at 06:56

score 2 · Answer 1 · edited May 23 '17 at 12:32

2

You have to understand how modulus works. =) when you apply modulus it gets divided and returns the "remainder"...

How Does Modulus Divison Work there is a very good explanation already posted.

edited May 23 '17 at 12:32

Community

1
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answered Sep 30 '15 at 06:58

Aven

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score 2 · Answer 2 · edited Sep 30 '15 at 06:59

2

30 % 4 = 2

because:

4 + 4 + 4 + 4 + 4 + 4 + 4 is 28 so 30 -28 = 2

edited Sep 30 '15 at 06:59

Madhawa Priyashantha

9,633
7
33
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answered Sep 30 '15 at 06:59

SWiggels

2,159
1
21
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score 0 · Answer 3 · answered Sep 30 '15 at 07:00

In Java, integer division returns the floor of the computation (rounds down to the nearest integer). This is why 30*4/100 comes out to 1.

On the other hand, modulus (%) is the remainder of integer division. Since 28 is divisible by 4, the remainder of 30/4 would be 2 (as 28+2=30).

score 0 · Accepted Answer · answered Sep 30 '15 at 07:01

The % operator is modulo, it takes the remainder after division of the two numbers, in your case it divides 30 by 4, the highest multiple is 7 as 7*4 = 28 now the remainder is 2, which is your answer, for the 33 case it does the same, 8*4 = 32 remainder is 1

How 30%4 output is 2 but if I write 30*4/100 output is 1

4 Answers4