Convert jsonObject Date to string in dd:mm:yyyy format in android

Question

I am getting jsonObject Date from database like this

JsonDate

"date_of":"\/Date(1251763200000)\/"

Method 1

public String getDatefromJson1(String jsonDate) {
        String timeString = jsonDate.substring(jsonDate.indexOf("(") + 1, jsonDate.indexOf(")"));
        String[] timeSegments = timeString.split("\\+");
        // May have to handle negative timezones
        int timeZoneOffSet = Integer.valueOf(timeSegments[1]) * 36000; // (("0100" / 100) * 3600 * 1000)
        int millis = Integer.valueOf(timeSegments[0]);
        Date time = new Date(millis + timeZoneOffSet);
        return new SimpleDateFormat("MM/dd/yyyy hh:mm a").format(time);
    }

Method 2

public String getDatefromJson(String jsonDate) {
        String json = jsonDate;
        String timestamp = jsonDate.split("\\(")[1].split("\\+")[0];
        Date createdOn = new Date(Long.parseLong(timestamp));
        System.out.println("createdOn---->"+createdOn);
        System.out.println(new SimpleDateFormat("MM/dd/yyyy hh:mm a").format(createdOn));
        return new SimpleDateFormat("MM/dd/yyyy hh:mm a").format(createdOn);
    }

Both the time getting same logcat error

java.lang.NumberFormatException: Invalid long: "1251763200000)/"
            at java.lang.Long.invalidLong(Long.java)
            at java.lang.Long.parse(Long.java)
            at java.lang.Long.parseLong(Long.java)
            at java.lang.Long.parseLong(Long.java)

As you see in the error, there is an extra `")/"` in your string...so you can't convert it to Long — Rami, Sep 30 '15 at 13:28

score 0 · Answer 1 · answered Sep 30 '15 at 13:45

0

Method 2:

instead of

"String timestamp = jsonDate.split("\(")[1].split("\+")[0];"

use this "

String timestamp2 = timeStamp.split("\(")[1].split("\)")[0];

"

answered Sep 30 '15 at 13:45

gairikd

1
1

Convert jsonObject Date to string in dd:mm:yyyy format in android

1 Answers1