4D visualization in Matlab (Surface and Mesh)

Question

I have four variables, x,y,z,t. I would like to show (x,y,z) in form of a surface such that the color of the surface is determined by t. I want to assign "t" to color bar. Now, color bar is corresponding to z, I want to have it corresponding to "t" my 4th variable.

Thank you for any help

Could you post your code? See http://stackoverflow.com/help/mcve — lhcgeneva, Sep 30 '15 at 20:46
X=1:10; Y=1:14; [x y]=meshgrid(X,Y);z=RESULT(:,1); t = RESULT(:,2) surf(x,y,z), colorbar — Emily, Sep 30 '15 at 20:55
Do **NOT** post code as comments. *Edit* the question by pressing the `edit` button below the tags on your question. — Adriaan, Sep 30 '15 at 21:51

Luis Mendo · Accepted Answer · 2015-09-30T21:03:28.053

5

That's very easy: just use

surf(x, y, z, t)

From the documentation,

surf(X,Y,Z,C) uses C to define color. MATLAB® performs a linear transformation on this data to obtain colors from the current colormap.

Here's an example:

x = linspace(0,pi,50);
y = linspace(0,pi/2,50);
z = bsxfun(@times, sin(x), sin(y.')); %'
t = bsxfun(@minus, x, y.'); %'// example data;
surf(x,y,z,t); %// draw surface
colorbar %// show colorbar

edited Sep 30 '15 at 21:03

answered Sep 30 '15 at 20:53

Luis Mendo

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Ghe, using `bsxfun` even though it's uncalled for, splendid. – Adriaan Sep 30 '15 at 21:52
@Adriaan The first idea that came to my mind was to use a separable function as an example. And that's what `bsxfun` does :-) – Luis Mendo Sep 30 '15 at 23:28

4D visualization in Matlab (Surface and Mesh)

1 Answers1