Receiving JSON data properly

Question

I'm receiving json data from my php page based on an ID value. The php is fine and I am receiving the JSON data + outputting it onto the textarea I want it in. Except, it comes with it's brackets and table name:

[{"analysis":TEST TEST TEST TEST}]

How do I make it output only the "TEST TEST TEST" part of my json output instead of all outputting all of it?

my async class

private class AsynMatchAnalysis extends AsyncTask<String, Void,String> {


        @Override
        protected String doInBackground(String... params) {
            // Create a new HttpClient and Post Header
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("http://192.168.0.3/ex/match_analysis.php");


            String jsonResult = "";
            try {
                // Add your data
                List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);

                nameValuePairs.add(new BasicNameValuePair("ID", passedID.toString()));
                httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                // Execute HTTP Post Request
                HttpResponse response = httpclient.execute(httppost);

                HttpEntity entity = response.getEntity();
                InputStream webservice = entity.getContent();

                try {
                    BufferedReader reader = new BufferedReader(new InputStreamReader(webservice, "iso-8859-1"), 8);

                    analysisView.setText("" + reader.readLine());
                    webservice.close();
                } catch (Exception e) {
                    Log.e("log_tag", "error converting result " + e.toString());
                }


                //   jsonResult = response.getEntity().getContent().toString();
                // passedView.append("" + jsonResult.toString());
                //System.out.println(jsonResult.toString());
            } catch (IOException e) {

            }
            return null;


        }

}

editted for clarity

please make your question clear,what are you asking and also correct your json string — Aakash, Oct 02 '15 at 15:48
You should Parse your response, just as you have been told. Check here http://stackoverflow.com/questions/15801247/parsing-a-json-array-from-http-response-in-java — Tosin Onikute, Oct 02 '15 at 15:51

score 0 · Accepted Answer · answered Oct 02 '15 at 16:10

0

You need to parse json for that like if the json is following:

[{"analysis":"abc","key2":"value"}]

This is how your parse json

//your jsonResult
JSONArray json_array=new JSONArray(jsonResult.toString());
for(int i=0;i< json_array.length ;i++){
 if(json_array.getJSONObject(i).has("analysis")){
  System.out.println(json_array.getJSONObject(i).getString("analysis"));
  }
if(json_array.getJSONObject(i).has("key2")){
  System.out.println(json_array.getJSONObject(i).getString("key2"));
  }
}

answered Oct 02 '15 at 16:10

Aakash

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For more reference you can check https://androidbeasts.wordpress.com/2015/08/04/json-parsing-tutorial/ – Aakash Oct 02 '15 at 16:11
Thanks for the link, it helped ! – Stevie Wonder Oct 02 '15 at 16:53

score 0 · Answer 2 · answered Oct 02 '15 at 16:49

I ended up getting it working. I appreciate the help given by you guys!

 BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
                   StringBuilder builder = new StringBuilder();
                    for(String line = null; (line = reader.readLine()) !=null;){
                        builder.append(line).append("\n");
                    }
                    JSONTokener tokener = new JSONTokener(builder.toString());
                    JSONArray finalAnswer = new JSONArray(tokener);

                    for(int i = 0; i < finalAnswer.length(); i++) {

                        JSONObject jsonChildNode;

                        try {


                            jsonChildNode = finalAnswer.getJSONObject(i);

                            String analysis = jsonChildNode.getString("analysis");

                            analysisView.setText(analysis.toString());
                        } catch (Exception e) {

                        }
                    }
                }
                    catch (Exception e) {
                    Log.e("log_tag", "error converting result " + e.toString());
                }

Receiving JSON data properly

2 Answers2