How to print the address of a float in c

Question

I want to create a program that prints the address of an int, a float and a double.

int main()
{
    int a;
    float b;
    double c;
    printf("\na:%d \nb:%f \nc:%lf", &a, &b, &c);
}

But in the end all I get is the address of the int. For the other two the answer is 0.00000.

score 2 · Answer 1 · answered Oct 03 '15 at 13:44

The correct format specifier for printing a memory address (pointer) is %p. You might as well cast the arguments into (void*) as the standard says that %p requires its arguments to be of type void*.

Using the wrong format specifier leads to Undefined Behavior.

ameyCU · Accepted Answer · 2015-10-03T13:46:57.387

2

Use specifier %p to print address.

printf("\na:%p \nb:%p \nc:%p",(void *)&a,(void *)&b,(void *)&c);

edited Oct 03 '15 at 13:46

answered Oct 03 '15 at 13:45

ameyCU

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You might want to add the necessary `void*`-casts. – EOF Oct 03 '15 at 13:46
@EOF Done that !! :) – ameyCU Oct 03 '15 at 13:47

score 1 · Answer 3 · answered Oct 03 '15 at 13:48

1

use %p to print address of void. printf doesn't seem to be able to pointer to float directly.

Try this: printf("\na:%p \nb:%p \nc:%p", (void*)&a, (void*)&b, (void*)&c);

answered Oct 03 '15 at 13:48

MikeCAT

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How to print the address of a float in c

3 Answers3