Why in Java printing a character prints character but adding two characters adds ascii?

Asked Oct 04 '15 at 18:21

Active Oct 04 '15 at 18:34

Viewed 50 times

Consider below code snippet

public class TestAsc
{
  public static void main(String args[]){
   System.out.println('a');
  }
}

Here O/P is a. Now the same code snippet with an addition as below.

public class TestAsc
{
  public static void main(String args[]){
   System.out.println('a' + 'a');
  }
}

Here o/p is 194. i.e addition of ASCII values. I knew by googling it out and from some posts in StackOverflow too that, addition of char would result in ASCII addition. But my question is why and how does it happen internally? And why isn't ASCII printed when I placed only 'a' in System.out.println!

edited Oct 04 '15 at 18:34

asked Oct 04 '15 at 18:21

Deca

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What do you mean internally? – Oct 04 '15 at 18:25
This is the syntax for it. You can print a twice by using - System.out.println("" + a + a); – Sanved Oct 04 '15 at 18:29
By internally, I meant how does the compiler/jvm acts to convert. It's a bit clear now on going through the link. – Deca Oct 04 '15 at 18:57

Why in Java printing a character prints character but adding two characters adds ascii?

0 Answers0