Obtain the drawable image according ID

Question

I have the following code:

Layout :

<ViewFlipper android:id="@+id/viewFlipper"
android:layout_height="fill_parent"
android:layout_width="fill_parent" >

<include layout="@layout/imagen3"/>

<include layout="@layout/imagen2"/>

Example layout imagen3 :

    <ImageView
    android:id="@+id/preview"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:background="@drawable/fondo3"/>

Java :

    Uri imageUri = Uri.parse("android.resource://" + getPackageName()
                    + "/drawable/" + "preview");

I want to create ImageURI with the id of the imageview.

because I want to share the image, the problem is that now I can only share the imagen2 which is what I put in Uri, example: Uri imageUri = Uri.parse ("android.resource: //" + getPackageName () + "/ Drawable /" + "imagen2"); — Kai, Oct 05 '15 at 16:02
I don't think that this is good idea because drawable is in [INTERNAL STORAGE](http://developer.android.com/guide/topics/data/data-storage.html#filesInternal) so another application do not have access to this memory. My advice is copy your image to [EXTERNAL STORAGE](http://developer.android.com/guide/topics/data/data-storage.html#filesExternal) — manzhda, Oct 05 '15 at 16:11

score 2 · Answer 1 · edited May 23 '17 at 11:52

2

I don't think that this is a good idea because drawable is in internal storage so another application do not have access to this memory.

First you could make a copy of your image to external storage

Or EVEN BETTER create Content Provider. This is the most correct and secure way in android to share content. Look here for example.

edited May 23 '17 at 11:52

Community

1
1

answered Oct 05 '15 at 16:32

manzhda

79
2

score 0 · Answer 2 · answered Oct 05 '15 at 16:02

You can get the R index for it (so you can use it) by using it's ID. Like this:

Integer imageIs =  getImageViewResource(R.id.preview)

The you can do more things with it, like change the image:

setImageViewResource(R.id.preview, newImage)

Why you would ever want to set that to a URI as a mystery...

score 0 · Answer 3 · answered Oct 05 '15 at 20:15

0

The problem is not whether internal or external, because it works correctly with the internal images, the problem is I want to use the same code to a different drawable corresponding to each image

answered Oct 05 '15 at 20:15

Kai

17
7

Obtain the drawable image according ID

3 Answers3