The two paragraphs below were copied from N4140 (emphasis are mine).
§5.3.4/11:
When a new-expression calls an allocation function and that allocation has not been extended, the new-expression passes the amount of space requested to the allocation function as the first argument of type
std::size_t
. That argument shall be no less than the size of the object being created; it may be greater than the size of the object being created only if the object is an array. For arrays ofchar
andunsigned char
, the difference between the result of the new-expression and the address returned by the allocation function shall be an integral multiple of the strictest fundamental alignment requirement (3.11) of any object type whose size is no greater than the size of the array being created. [ Note: Because allocation functions are assumed to return pointers to storage that is appropriately aligned for objects of any type with fundamental alignment, this constraint on array allocation overhead permits the common idiom of allocating character arrays into which objects of other types will later be placed. —end note ]
§5.4.3/12
When a new-expression calls an allocation function and that allocation has been extended, the size argument to the allocation call shall be no greater than the sum of the sizes for the omitted calls as specified above, plus the size for the extended call had it not been extended, plus any padding necessary to align the allocated objects within the allocated memory.
I can understand §5.3.4/11, but the notion of an allocation function which has been extended is incomprehensible to me, as stated above in §5.4.3/12.