I want every character possible (letters,numbers,everyting) except: !"#$'*+,/:;\|`
Is this correct? [^!"#$'*+,/:;\`|]
I made it work using http://www.regextester.com/ and your suggestions
*WORKS--> [^!"#$'*+,/:;\\`|]
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Liev04
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1regex101.com ... you can try here....and come back with a specific question....and also tag the flavor of regex being used by you – vks Oct 09 '15 at 17:08
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My code ignore the "\" ...any tips? – Liev04 Oct 09 '15 at 17:10
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Which language you use it for? – vks Oct 09 '15 at 17:11
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1To match a literal ``\``, you need to double it. Please state your programming language and post the code you have. – Wiktor Stribiżew Oct 09 '15 at 17:11
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Why do not accept `\\` ? What language are you using? – Oct 09 '15 at 17:12
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the doble \\ fixed my problem – Liev04 Oct 09 '15 at 17:14
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Read this: _http://stackoverflow.com/q/6105476/4227915_ – Oct 09 '15 at 17:15
1 Answers
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A regex pattern to match a single \:
\\
It means you need to escape a backslash by adding another backslash to it. So, you need to use
[^!"#$'*+,/:;\\`|]
^^
Note that if you use it in a regular string literal in some programming language, you will have to double each of the backslashes (so that there are 4 backslashes).
Wiktor Stribiżew
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