Get sorted dict values

Question

How would I get the dictionary values based on the sorted key? For example:

d = {
     'first': 'asdf'
     'second': 'aaaa'
}

==> ['asdf', 'aaaa']

I was thinking something along the lines of:

sorted(x.item(), sort=...)

How would this be done?

Possible duplicate of [Sort a Python dictionary by value](http://stackoverflow.com/questions/613183/sort-a-python-dictionary-by-value) — yurib, Oct 09 '15 at 18:45

Eugene Soldatov · Accepted Answer · 2015-10-09T18:45:46.503

4

Use sorted keys:

d = {'first': 'asdf', 'second': 'aaaa'}
values = [d[x] for x in sorted(d)]

edited Oct 09 '15 at 18:45

answered Oct 09 '15 at 18:43

Eugene Soldatov

9,755
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1

no need to use `.keys()`. Just `d` will iterate the keys – JBernardo Oct 09 '15 at 18:45

score 0 · Answer 2 · answered Oct 09 '15 at 18:42

0

You can use a list comprehension like so:

>>> d = {
...          'first': 'asdf',
...          'second': 'aaaa'
...     }
>>> [item[1] for item in sorted(d.items(), key=lambda x: x[0])]
['asdf', 'aaaa']

answered Oct 09 '15 at 18:42

David542

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Get sorted dict values

2 Answers2