Global variable inside of function

Question

Code below prints produces error:

Notice: Undefined variable: x in C:\wamp\www\h4.php on line 9

and output:

Variable x inside function is:
Variable x outside function is: 5

Code:

<html>
<body>

<?php
$x = 5; // global scope

function myTest() {
    // using x inside this function will generate an error
    echo "<p>Variable x inside function is: $x</p>";
} 
myTest();

echo "<p>Variable x outside function is: $x</p>";
?>

</body>
</html>

What gets wrong with x global variable inside of myTest function?

Best to pass it in your function. Global is often frowned upon by many coders. — Funk Forty Niner, Oct 13 '15 at 11:05

score 2 · Accepted Answer · answered Oct 13 '15 at 10:59

2

Change to this:

function myTest() {
    global $x;
    // using x inside this function will generate an error
    echo "<p>Variable x inside function is: $x</p>";
}

The global command says to use the global value of $x rather than a private one.

answered Oct 13 '15 at 10:59

Chris Lear

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Or You can just type error_reporting(0); for preventing notices and errors. – Sagar Sadrani Oct 13 '15 at 11:08
1

No, suppressing errors is very much not what is wanted. The OP wants the global value of `$x` inside the function. – Chris Lear Oct 13 '15 at 11:10
Ok then just define it global as you said...!! (Y) – Sagar Sadrani Oct 13 '15 at 11:12

score 2 · Answer 2 · answered Oct 13 '15 at 10:59

To access global variable you need to define with 'global' keyword with in the function.After define it you can access that global variable.

      $x = 5; // global scope

        function myTest() {
//use global keyword to access global variable
            global $x;
            // using x inside this function will generate an error
            echo "<p>Variable x inside function is: $x</p>";
        } 
        myTest();

    echo "<p>Variable x outside function is: $x</p>";

Global variable inside of function

2 Answers2