Python - Sorting Dictionaries

Question

I'm having some trouble with this Python. I'm trying to sort a dictionary alphabetically, from min to max (with values) and from max to min (by values). How can I do this?

Note: I can't get max to min working

stocks = {
    'GOOG': 520.24,
    'FB': 331.28,
    'XMZN': 89.72,
    'APPL': 112.31
}

# for min to max
print(sorted(zip(stocks.values(), stocks.keys())))

# for alphabetically
print(sorted(zip(stocks.keys(), stocks.values())))

# for max to min
print(sorted(zip(stocks.values(), stocks.keys(), reverse))

Possible duplicate of [Python list sort in descending order](http://stackoverflow.com/questions/4183506/python-list-sort-in-descending-order) — The6thSense, Oct 14 '15 at 06:59

score 4 · Answer 1 · answered Oct 14 '15 at 06:56

4

Keyword arguments must be given a value, otherwise the identifier will be used as a name.

print(sorted(zip(stocks.values(), stocks.keys(), reverse=True))

answered Oct 14 '15 at 06:56

Ignacio Vazquez-Abrams

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up voted but possible duplicate of [this](http://stackoverflow.com/questions/4183506/python-list-sort-in-descending-order/4183540#4183540) :p – The6thSense Oct 14 '15 at 06:58

score 2 · Answer 2 · answered Oct 14 '15 at 06:57

2

stocks = {
'GOOG': 520.24,
'FB': 331.28,
'XMZN': 89.72,
'APPL': 112.31
}

print sorted(stocks.items(),key=lambda x:x[1],reverse=True)

You can simply do this instead of zip and all

answered Oct 14 '15 at 06:57

vks

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score 1 · Answer 3 · answered Oct 14 '15 at 06:55

1

You can reverse the list using [::-1]

# for max to min
print(sorted(zip(stocks.values(), stocks.keys()))[::-1])

Output:

[(520.24, 'GOOG'), (331.28, 'FB'), (112.31, 'APPL'), (89.72, 'XMZN')]

answered Oct 14 '15 at 06:55

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Python - Sorting Dictionaries

3 Answers3