swift inner,outter function parameters

Question

I declared a function, for example,

func test(a: Int, b: Int)

but when I invoke it, i have to put a code like this:

test(12, b: 32)

It looks so weird !

I declared the test function with symmetrical parameters, but the function call is not symmetric.

How can I declare the function to make the function call exactly like this:

test(12, 32)

Take a look at this answer : http://stackoverflow.com/questions/24045890/why-does-a-function-call-require-the-parameter-name-in-swift . — iamyogish, Oct 15 '15 at 12:30
Have a look at ["Function Parameter Names"](https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/Functions.html#//apple_ref/doc/uid/TP40014097-CH10-ID166) in the Swift book ... it is all documented. — Martin R, Oct 15 '15 at 12:32
imyogish, Martin R thx, both of u! I seems the # has been canceled in swift2! I get it thx! — Microos, Oct 15 '15 at 12:37

score 2 · Accepted Answer · answered Oct 15 '15 at 12:30

2

The full form of function declarations is:

func test(parameterLabelA parameterNameA: Type, parameterLabelB parameterNameB: Type)

By default if you omit labels as in:

func test(a: Int, b: Int)

the following form is inferred:

func test(_ a: Int, b b: Int)

where _ means no label.

In order to remove the b label you can declare your function as:

func test(a: Int, _ b: Int)

Note however that this is not the recommended style.

answered Oct 15 '15 at 12:30

Nicholas H.

1

like Nicholas points out, it is not the recommended style, it could lead to confusion. Just rather use: func( test test : Int, test2 test2 : Int) – dirtydanee Oct 15 '15 at 12:35

Adam · Answer 2 · 2015-10-15T12:32:24.250

1

Simple as that:

func test(x : Int, _ y : Int) {
    print(x)
    print(y)
}

Edit: added inner parameter names.

edited Oct 15 '15 at 12:32

answered Oct 15 '15 at 12:29

Adam

How do you access the values of the parameters in the body of the function in this form? – Nicholas H. Oct 15 '15 at 12:31

2 Answers2