var t1 = [2,4,7,9];
var t2 = t1;
console.warn(t2); // [2, 4, 7, 9]
t1[1] = 7;
console.warn(t2); // [2, 7, 7, 9]
Why? :) I can't understand. t2 is inheits t1?
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Davit Tchkoidze
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Arrays are passed as "reference of a value", see the duplicate for a much longer explanation, and that's why you're working with the same array in both variables, and not unique arrays. – adeneo Oct 15 '15 at 17:57
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1To solve the issue for you, if you want to copy the array, you can do `var t2 = t1.slice();` – adeneo Oct 15 '15 at 17:58