Open many levels tuple in Python

Question

I have a two dictionaries:

nums = {u'+123456789': [u'google.com', u'yahoo.com', u'183.6.43.21'], u'+9876543210': [u'amazon.com', u'yahoo.com', u'bit.ly'] ... }

that contains phone number and domains linked to this number

and

availability = {u'yahoo.com': 0.3, u'amazon.com': 0.0, u'183.6.43.21': 0.0, u'bit.ly': 0.9, u'google.com': 1.0}

I need to attach this dictionaries together, so I can send sms to each phone number contains text with domains availability.

I make a function, that can do that:

for key, value in nums.iteritems(): 
    for domain, av in availability.iteritems():
        if domain in value:
            if key in dct:
                a = dct[key], domain
                dct.update({key: a})
            else:
                dct[key] = domain

for key in dct:
    send_to(phone=key, text=dct[key])

It works, but when the only one domain attached to phone number in nums - it comes as a string, and sometimes output can looks like that:

Send to:  +1234567890
(((u'183.23.45.65', u'google.com'), u'yahoo.com'), u'bit.ly')

Is there any way to generate the tuple with the only one layer? Or maybe the best way is to recursively open this tuple?

You should add what `dct` should look like. – Anand S Kumar Oct 16 '15 at 06:26 — Anand S Kumar, Oct 16 '15 at 06:26
The common term is "flatten" rather than "open." – TigerhawkT3 Oct 16 '15 at 06:27 — TigerhawkT3, Oct 16 '15 at 06:27

Open many levels tuple in Python

0 Answers0