How to download a file and get the path location locally

Question

I have a URL i.e http://downloadplugins.verify.com/Windows/SubAngle.exe . If I paste it on the tab and press enter then the file (SubAngle.exe) is getting downloaded and saved in the download folder. This is a manual process. But it can be done with java code. I wrote the code for getting the absolute path with the help of the file name i.e SubAngle.exe.

Requirement:- With the help of the URL file gets downloaded,Verify the file has been downloaded and returns the absolute path of the file.

where  locfile is "http://downloadplugins.verify.com/Windows/SubAngle.exe"  

  public String downloadAndVerifyFile(String locfile) {
     File fileLocation = new File(locfile); 
     File fileLocation1 = new File(fileLocation.getName());
     String fileLocationPath = null;
     if(fileLocation.exists()){
      fileLocationPath = fileLocation1.getAbsolutePath();
  
     }
     else{
         throw new FileNotFoundException("File with name "+locFile+" may not exits at the location");
     }
     return fileLocationPath;
}

No, you should have a local path, which reflects a location on your disk, something like C:\Users\{your user name}\Downloads — MadProgrammer, Oct 20 '15 at 08:32
related: http://stackoverflow.com/questions/43157/easy-way-to-write-contents-of-a-java-inputstream-to-an-outputstream/51753#51753 — Thomas Weller, Oct 20 '15 at 13:29
Possible duplicate of [How to download and save a file from Internet using Java?](http://stackoverflow.com/questions/921262/how-to-download-and-save-a-file-from-internet-using-java) — Thomas Weller, Oct 20 '15 at 13:35

score 2 · Answer 1 · edited Feb 17 '19 at 11:01

easy and general function that im using:

import org.apache.commons.io.FileUtils;

public static void downLoadFile(String fromFile, String toFile) throws MalformedURLException, IOException {
        try {
            FileUtils.copyURLToFile(new URL(fromFile), new File(toFile), 60000, 60000);

        } catch (FileNotFoundException e) {
            e.printStackTrace();
            System.out.println("exception on: downLoadFile() function: " + e.getMessage());
        }
    }

score 1 · Answer 2 · answered Feb 15 '17 at 08:58

1

Instead of writing this huge code, go for Apache's commons.io Try this:

URL ipURL = new URL("inputURL");
File opFile = new File("outputFile");
FileUtils.copyURLToFile(ipURL, opFile);

answered Feb 15 '17 at 08:58

Varshney P.

208
1
12

Ravindra babu · Answer 3 · 2015-10-20T16:56:27.963

0

Code to DownloadFile from URL

import java.net.*;
import java.io.*;

public class DownloadFile {
    public static void main(String[] args) throws IOException {
        InputStream in = null;
        FileOutputStream out = null;
        try {
            // URL("http://downloadplugins.verify.com/Windows/SubAngle.exe");
            System.out.println("Starting download");
            long t1 = System.currentTimeMillis();
            URL url = new URL(args[0]);
            // Open the input and out files for the streams
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            in = conn.getInputStream();
            out = new FileOutputStream("YourFile.exe");
            // Read data into buffer and then write to the output file
            byte[] buffer = new byte[8192];
            int bytesRead;
            while ((bytesRead = in.read(buffer)) != -1) {
                out.write(buffer, 0, bytesRead);
            }
            long t2 = System.currentTimeMillis();
            System.out.println("Time for download & save file in millis:"+(t2-t1));
        } catch (Exception e) {
            // Display or throw the error
            System.out.println("Erorr while execting the program: "
                    + e.getMessage());
        } finally {
            // Close the resources correctly
            if (in != null) {
                in.close();
            }
            if (out != null) {
                out.close();
            }
        }

    }

}

Configure the value of fileName properly to know where the file is getting stored. Source: http://www.devmanuals.com/tutorials/java/corejava/files/java-read-large-file-efficiently.html

The source was modified to replace local file with http URL

Output:

java DownloadFile http://download.springsource.com/release/TOOLS/update/3.7.1.RELEASE/e4.5/springsource-tool-suite-3.7.1.RELEASE-e4.5.1-updatesite.zip

Starting download

Time for download & save file in millis:100184

edited Oct 20 '15 at 16:56

answered Oct 20 '15 at 08:32

Ravindra babu

37,698
11
250
211

1

if you copy paste, at least use url and file provided by OP, also note your link is broken – Jordi Castilla Oct 20 '15 at 08:33
That may be typo error. I have provided working link in "download' – Ravindra babu Oct 20 '15 at 08:35
What if the size of file is greater than 1 GB ? – Little bird Oct 20 '15 at 12:56
It will handle since we are writing byte array of size 1024 bytes. It don't need 1 GB RAM but you just need 1 GB disk space. Let me know if you face issues with 1 GB file size. Add out.flush () after out.write() – Ravindra babu Oct 20 '15 at 13:13
On a different note of reading large file, have a look at this post: http://stackoverflow.com/questions/18508836/java-outofmemoryerror-in-reading-a-large-text-file/31724120#31724120 – Ravindra babu Oct 20 '15 at 13:20
@ravindra: really? `byte[] response` sounds much like everything is in that byte[] before it gets written to disk – Thomas Weller Oct 20 '15 at 13:21
Small change is required in my code. After out.write (),write to fos immediately. Have a look at : http://www.devmanuals.com/tutorials/java/corejava/files/java-read-large-file-efficiently.html – Ravindra babu Oct 20 '15 at 13:23
2

Seriously, why would you read the file into a ByteArrayOutputStream? Obviously this fails if the file is too big. Not to mention that it is pointless and inefficient. – Stephen C Oct 20 '15 at 13:25
Have you checked the license of the code that you are copying? – Thomas Weller Oct 20 '15 at 13:26
@ravindra : Are you sure that this will work for >1GB file size?Because stiil byte array [1024] is being defined in the code. Thanks – Little bird Oct 20 '15 at 13:52
I have changed the code to take filename as input from args[0]. 117 MB file is downloaded in 2 mins. e.g. java DownloadFile http://download.springsource.com/release/TOOLS/update/3.7.1.RELEASE/e4.5/springsource-tool-suite-3.7.1.RELEASE-e4.5.1-updatesite.zip – Ravindra babu Oct 20 '15 at 13:58

How to download a file and get the path location locally

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