Python-String to Bytes conversion. Double BackSlash issue

Question

I've got a problem. I've this string:

a=O\x8c\x90\x05\xa1\xe2!\xbe

If i use:

c=str.encode(a)

This is the result:

b'O\\x8c\\x90\\x05\\xa1\\xe2!\\xbe'

I need those double backslash to be single backslash and i really need that type of data to be BYTES. I need to return this:

c=b'0\x8c\x90\x05\xa1\xe2!\xbe'

And type(c)==bytes Any idea?

what does `print(repr(a))` give? – Anand S Kumar Oct 21 '15 at 11:15 — Anand S Kumar, Oct 21 '15 at 11:15
Sry. This: 'O\\x8c\\x90\\x05\\xa1\\xe2!\\xbe' – Teo Albano Oct 21 '15 at 11:17 — Teo Albano, Oct 21 '15 at 11:17

Anand S Kumar · Accepted Answer · 2015-10-21T16:28:50.500

21

You can use str.decode() with encoding as unicode-escape . Then decode it back using the required encoding to get back your bytes array. Example -

c = a.decode('unicode-escape').encode('<required encoding>')

Demo -

>>> a
b'O\\x8c\\x90\\x05\\xa1\\xe2!\\xbe'
>>> c = a.decode('unicode-escape').encode('ISO-8859-1')
>>> c
b'O\x8c\x90\x05\xa1\xe2!\xbe'

edited Oct 21 '15 at 16:28

answered Oct 21 '15 at 11:23

Anand S Kumar

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Nvm. didn't notice c is Bytes. – Teo Albano Oct 21 '15 at 11:29
Still not getting what i want. I need this output --> c=b'0\x8c\x90\x05\xa1\xe2!\xbe' Your solution gives me this: b'O\xc2\x8c\xc2\x90\x05\xc2\xa1\xc3\xa2!\xc2\xbe' – Teo Albano Oct 21 '15 at 11:36
Thats because `\xe2` is not valid `utf-8` . Use a valid encoding and it should work – Anand S Kumar Oct 21 '15 at 11:53
@TeoAlbano Check now, using `ISO-8859-1` should work. – Anand S Kumar Oct 21 '15 at 11:54
1

You are a GOD. If you are dumping and data via DUMP in Redis and you're trying to RESTORE it, you will absolutely need to decode, then encode it back using `ISO-8859-1`. – John Paul Barbagallo Oct 17 '19 at 15:11

Python-String to Bytes conversion. Double BackSlash issue

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