I have the following python list :-
a=[['t1', ['a', 'c']], ['t2', ['b']], ['t2', ['b']]]
now it contains duplicate lists within it ['t2', ['b']] 2 times
I want to return true if the list contains duplicates.
Can anyone please help me how to do so ?
I tried to use the set function but it is not working here !
If your aim is to remove duplicates, this answer might be helpful:
unique_a = [i for n, i in enumerate(a) if i not in a[:n]]
You can rewrite it this way:
has_duplicates = lambda l: True in [(i in l[:n]) for n, i in enumerate(l)]
You can call it this way:
has_duplicates(a) # True
If you are free to represent your list a as a list of tuples/records:
b = [(item[0], tuple(item[1])) for item in a]
(or, in the first place):
a = [('t1', ('a', 'c')), ('t2', ('b')), ('t2', ('b'))]
Then the items become hashable and you can use collections.Counter:
from collections import Counter
c = Counter(b)
So you can find duplicates like:
duplicated_items = [key for key, count in c.iteritems() if count > 1]
(Or you can use set):
has_duplicates = len(set(b)) < len(b)
