Java - Convert a string to double with 10 or more decimals

Question

How do I convert a string such as 40,123.012345678901 to a double?

double d = Double.parseDouble("40,123.012345678901");

throws a number format exception.

Thanks

Possible duplicate of [Best way to parseDouble with comma as decimal separator?](http://stackoverflow.com/questions/4323599/best-way-to-parsedouble-with-comma-as-decimal-separator) — ccc, Oct 26 '15 at 18:44

score 2 · Answer 1 · answered Oct 26 '15 at 18:34

2

If there is no way to get rid of comma(,) you may use another approach:

NumberFormat format = NumberFormat.getInstance(Locale.US);
Number number = format.parse("40,123.012345678901");
double d = number.doubleValue();

answered Oct 26 '15 at 18:34

algor

404
2
8

score 1 · Answer 2 · answered Oct 26 '15 at 18:30

1

The simplest way is to remove comma:

double d = Double.parseDouble("40,123.012345678901".replace(",", ""));

answered Oct 26 '15 at 18:30

hsz

148,279
62
259
315

score 1 · Answer 3 · answered Oct 26 '15 at 18:31

1

A double is limited to around 16 digits of precision. If you need more precision, you should use BigDecimal.

BigDecimal bd = new BigDecimal("40,123.012345678901".replace(",", ""));

answered Oct 26 '15 at 18:31

Peter Lawrey

525,659
79
751
1,130

score 0 · Answer 4 · answered Oct 26 '15 at 18:30

0

You should remove the comma (,) from your string:

This will work:

double d = Double.parseDouble("40123.012345678901");

answered Oct 26 '15 at 18:30

Prem

157
7

score 0 · Answer 5 · answered Oct 26 '15 at 18:40

Use NumberFormat to get double value,

    try {
        NumberFormat format = NumberFormat.getInstance();
        Number parse = format.parse("40,123.012345678901");
        System.out.println(parse.doubleValue());
    } catch (ParseException ex) {
        System.out.println(ex.getMessage());
    }

Java - Convert a string to double with 10 or more decimals

5 Answers5