How to update javascript variable after ajax call back

Question

var x =1;

$(document).on('click','.classname',function(){
console.log(x);
});

$.ajax({
        type:'post',
        url:tmplUri+'/ajax/test.php',
        cache:false,
        async:false,
        data:{journey:'yes'},
        success: function(data)
        {
          x = data;
         }
});

after ajax call i need to update the variable on that page

Please give any suggestion for this issue

maybe the ajax failed?are you sure it is a success also dont use ASYNC FALSE — guradio, Oct 27 '15 at 10:28
Is the success method is called ? Try by adding the "debugger" keyword in the method, and launch the page with the debugger tool (F12). — Paul DS, Oct 27 '15 at 10:29
Your issue lloks like a scope one but anyway this isn't the way you should hanlde result from ajax request, using a global var. See for better idea: http://stackoverflow.com/questions/14220321/how-to-return-the-response-from-an-asynchronous-call — A. Wolff, Oct 27 '15 at 10:32
Try this with your php URL: http://jsfiddle.net/qq3zg18z/ Your code looks good! — Rayon, Oct 27 '15 at 10:35

Shailendra Sharma · Answer 1 · 2015-10-27T10:38:59.407

2

for this you need a globle variable, just Call a another function to reset you variable after ajax call

  var x // make it globle


    $(document).on('click','.classname',function(){
    console.log(x);
    });

    function resetx(){
     x =1;
    }


    $.ajax({
            type:'post',
            url:tmplUri+'/ajax/test.php',
            cache:false,
            async:false,
            data:{journey:'yes'},
            success: function(data)
            {
              x = data;
             }
    });


calling hierarchy

ajaxcall 
resetx

than check you variable it will give you 1

here the fiddle

edited Oct 27 '15 at 10:38

answered Oct 27 '15 at 10:32

Shailendra Sharma

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In example it looks global too! – Rayon Oct 27 '15 at 10:33
i know wait i am creating fiddle – Shailendra Sharma Oct 27 '15 at 10:34
1

@RayonDabre Ya but i guess it isn't. Opening post missing some context for sure – A. Wolff Oct 27 '15 at 10:34

How to update javascript variable after ajax call back

1 Answers1