echoing dynamically generated variable

Question

set CSS_FOLDER_SOURCE=.\css
set JS_FOLDER_SOURCE=.\js



for %%A in (JS, CSS ) do (

    if defined %%A_FOLDER_SOURCE (
        echo  %%%A_FOLDER_SOURCE%%
    )
)

I want to read the contents of both folders. But don't know how to dynamically generate the FOLDER_SOURCE names

Possible duplicate of [How would I call a dynamic variable name?](http://stackoverflow.com/questions/22621708/how-would-i-call-a-dynamic-variable-name) — wOxxOm, Oct 27 '15 at 15:11
If this duplicate is okay I'll delete my answer as unnecessary. — wOxxOm, Oct 27 '15 at 15:11
You may review the details of this management at http://stackoverflow.com/questions/10166386/arrays-linked-lists-and-other-data-structures-in-cmd-exe-batch-script/10167990#10167990 — Aacini, Oct 27 '15 at 15:13

score 2 · Accepted Answer · answered Oct 27 '15 at 15:10

2

Use Delayed expansion:

setlocal enableDelayedExpansion

............
for %%A in (JS CSS) do (
    echo !%%A_FOLDER_SOURCE!
)

answered Oct 27 '15 at 15:10

wOxxOm

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And how may I assign this !%%A_FOLDER_SOURCE! to another variable? – user3733648 Oct 27 '15 at 15:52
`set anotherVariable=!%%A_FOLDER_SOURCE!`, then you can use it `echo !anotherVariable!` – wOxxOm Oct 27 '15 at 16:01

echoing dynamically generated variable

1 Answers1