Regular expression to fetch lines evaluating only one part of a string, java

Question

I'm trying to find the regular expression to match only a part of the pattern

For an example text is :

GoodClass.NiceMethod
BadClass.NiceMethod
Badclass2.NiceMethod
Verybadclass.NiceMethod
GoodClass.NiceMethod
BadClass.NiceMethod
Badclass2.NiceMethod
GoodClass.NiceMethod

how can I get all lines where 'NiceMethod' does not follow 'GoodClass'

Possible duplicate of [Using Java to find substring of a bigger string using Regular Expression](http://stackoverflow.com/questions/600733/using-java-to-find-substring-of-a-bigger-string-using-regular-expression) — angelcool.net, Oct 29 '15 at 18:05

anubhava · Accepted Answer · 2015-10-28T03:33:31.420

1

You can use negative lookbehind:

String regex = "(?<!GoodClass\\.)\\bNiceMethod\\b";

edited Oct 28 '15 at 03:33

answered Oct 27 '15 at 16:15

anubhava

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You typo'ed `Good` as `GooD`, and the code also allow `VeryNiceMethod` to match. – nhahtdh Oct 28 '15 at 03:07

Regular expression to fetch lines evaluating only one part of a string, java

1 Answers1