simple escape parentheses to count them

Asked Oct 28 '15 at 21:50

Active Oct 28 '15 at 21:50

Viewed 17 times

I am trying to make separate counts of open and closed parentheses in a JavaScript string. How can I write the regex to accomplish this?

Here is what I have so far, which is throwing errors:

($scope.somevariable.match(new RegExp("\(", "g")) || []).length

and:

($scope.somevariable.match(new RegExp("\)", "g")) || []).length

The results of google searches on this topic all have very complicated expressions. This question is about a very simple example of just counting the number of ( and ) separately.

I am using AngularJS.

asked Oct 28 '15 at 21:50

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It is another duplicate. Double ``\`` in a regexp constructor, or best - use `.match(/\)/g)`. – Wiktor Stribiżew Oct 28 '15 at 21:53
This is a duplicate, it can be solved using [this answer](http://stackoverflow.com/a/432503/3499931). – Trasiva Oct 28 '15 at 21:55

simple escape parentheses to count them

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