Javascript variables appended in a string not getting replaced with it's original value

Question

The string ''+notify_name+' likes your post.' is coming from the database. We are storing this static string in the database.

variable ntfnFound[0].body contains this string that we fetched from the database.

var notify_name = 'tintu';

console.log(ntfnFound[0].body);   /* ''+notify_name+' likes your post.' */

var body = ntfnFound[0].body;

console.log(body);   /* ''+notify_name+' likes your post.' */

console.log(''+notify_name+' likes your post.');   /*tintu likes your post*/

My question is,

In the above code why not 'console.log(body);' displays 'tintu likes your post' ??

or

Why +notify_name+ is not getting replaced ??

Also is there any solution for converting the string in 'var body' to 'tintu likes your post' ??

IN the following code works,

console.log(''+notify_name+' likes your post.');   /*tintu likes your post*/

It sounds like you want to store a template in the db and then apply some data to that template when it's rendered? — Shanimal, Oct 29 '15 at 14:28

score 1 · Answer 1 · edited May 23 '17 at 12:14

1

My first guess would be: You saved the STRING in your DB, when pulling it out, it is still a String, so must likely the ' and + are escaped: \' and \+.

What you are trying to accomplish is to save a String in your DB where you later want to insert the value of your variable.

My approach would be: saving something like "{0} likes your post" and then use some kind of printf function on it.

have a look at : JavaScript equivalent to printf/string.format

edited May 23 '17 at 12:14

Community

1
1

answered Oct 29 '15 at 06:40

null

45
1
5

I`m getting an error against format() - undefined is not a function. – Reshma Reghunatha Panicker Oct 29 '15 at 07:11
Format ist not a buildin Funktion in JS, you have to include a library or write your own. Like in the topic i linked: http://stackoverflow.com/a/4673436/3801048 – null Oct 29 '15 at 21:23

score 0 · Answer 2 · answered Oct 29 '15 at 06:36

There are no automagic replacements in JS - you'll have to it yourself with body.replace("+notify_name+",notify_name);.

The reason it worked in the log is. because JS did what you told it to do: '' is an empty string, then you catenated the name and the text 'likes your post'.

Javascript variables appended in a string not getting replaced with it's original value

2 Answers2