Convert char* to uint16_t in C

Question

I have char array like

char* str = 0x058f;

What should i do to convert this value to int and uint16_t and print correctly this value by uint16_t type?

That mean i want the uint16_t result is 058f as well:

 uint16_t result = 0x058f;

["What is the XY problem?"](http://meta.stackexchange.com/questions/66377/what-is-the-xy-problem) — Ignacio Vazquez-Abrams, Oct 30 '15 at 03:11
Do you mean to convert `char* str = "0x058f";`? Review `sscanf()` and `SCNx16` from ``. — chux - Reinstate Monica, Oct 30 '15 at 03:12
this problem doesn't show any research effort at all. google `c hex to int`, bunches of answers: http://stackoverflow.com/questions/10156409/convert-hex-string-char-to-int — Jason Hu, Oct 30 '15 at 03:14

score 2 · Answer 1 · answered Oct 30 '15 at 03:32

2

You can use strtol to convert string to integer value

*char* str = "0x058f";
result = strtol(str,NULL,16);
printf("result = %x\n",result);*

I hope this helps.

answered Oct 30 '15 at 03:32

Sami

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chux - Reinstate Monica · Accepted Answer · 2015-10-30T03:32:22.420

1

convert this value to int and uint16_t and print correctly this value by uint16_t

int main(void) {

  char* str = "0x058f";

  int i;
  unsigned u;
  if (sscanf(str, "%x", &u) != 1) 
    Handle_Failure();
  i = (int) u;

  uint16_t u16;
  if (sscanf(str, "%" SCNx16, &u16) != 1) 
    Handle_Failure();

  printf("i: 0x%04x  i16: 0x%04" PRIx16 "\n", i, u16);
  return 0;
}

i: 0x058f  i16: 0x058f

edited Oct 30 '15 at 03:32

answered Oct 30 '15 at 03:18

chux - Reinstate Monica

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Thanks so much, i got it ~ – Tiktac Oct 30 '15 at 03:37

Convert char* to uint16_t in C

2 Answers2