Deallocate memory from 2D mixed array and vector

Question

a 2D and 3D array vectors are defined and used throughout a simulation, they are very large in size so deallocation is neccesary.

array<vector<double>, n> A;
array<vector<vector<double>, n>, m> B;

what is the proper way?

Do you want the arrays to go away or the storage of the vectors? — NathanOliver, Oct 30 '15 at 16:30

score 3 · Accepted Answer · answered Oct 30 '15 at 16:30

3

just let them go out of scope:

{
    array<vector<double>, n> A;
    array<vector<vector<double>, n>, m> B;

    // use arrays ...

} // leave scope, arrays will be deallocated

answered Oct 30 '15 at 16:30

m.s.

what do u mean? when simulation is done they are deallocated? – jarhead Oct 30 '15 at 16:36
@jarhead they will be deallocated whenever the scope they are defined in is left – m.s. Oct 30 '15 at 16:38
2

If you put '{}' around your variable, they are deallocated after the '}'. http://stackoverflow.com/questions/10080935/when-is-an-object-out-of-scope – ARG Oct 30 '15 at 16:41
@ARG so basically when it is out of main() it is out of scope as well – jarhead Oct 30 '15 at 18:27
1

Yes, and also if you put them in code like this `int main() { { array, n> A; array, n>, m> B; // do whatever you want with them } // out of scope so arrays will be deallocated // do whatever else you want return 0; }` – ARG Oct 30 '15 at 18:53
But IMHO there is no need to deallocate the variable which are allocated on stack – ARG Oct 30 '15 at 19:00

1 Answers1