I have 5 php files currently set up in my cPanel cron jobs section running at different times. Ideally, I would like to run these jobs sequentially as each one finishes. Is there a command I can do to make that happen?
For example, I don't know the syntax but can I do something like:
/usr/local/bin/php -f /home/public_html/fileA.php THEN /home/public_html/fileB.php
Please see the answer here:
Running two commands sequentially in a cron job?
If you'd rather read it here, basically you can separate the commands with "&&" and one will run when the other finishes. Or, a more logical solution to me, is to make one file and have it execute each of the files you want it to.
yes, there is, you can run multiple cron jobs on single line, and each job will executed when first one is finished.
I recommend you to read this
you need to put && between the crons
So your cron will look something like this.
/home/public_html/fileA.php && /home/public_html/fileB.php && /home/public_html/fileC.php
and so on, add whatever number you want to. As a note, the && will only run the next command if the current command completes successfully. If you have a script that may error out, simply use a ; which is a line buffer. Do not use a line buffer if you are moving, tarring, or deleting.
You can use "&&" between each call like so:
/usr/local/bin php -f /home/public_html/fileA.php && /usr/local/bin php -f /home/public_html/fileB.php && /usr/local/bin php -f /home/public_html/fileC.php
...and so on. :)
