I have create my own malloc
function and it works properly. but I want to create another malloc
using only array without struct
. Is that possible to create without struct
? This is my code.
#include <stdio.h>
char memory[20000];
int freeMem=20000;
typedef struct{
int start;
int end;
}chunk;
void *MyMalloc(int size){
printf("\nMemory Size= %d ",size);
if(size==0){
printf("0 means no memory\n");
return 0;
}
int memsize=20000;
chunk *p=(chunk *)&memory[0];
if(freeMem >= size+sizeof(chunk)){
while(p<(chunk *)&memory[19999]){
if(p->start==0){
if(p->end !=0){
if(size+sizeof(chunk)< (p->end - (int)p)){
p->start=(int)p+8;
p->end=(int)p+8+size;
freeMem = freeMem-(size+8);
printf("free Mem : %d\n",freeMem);
return (int *)p->start;
}
else{
p=(chunk *)p->end;
continue;
}
}
else{
p->start=(int)p+8;
p->end=(int)p+8+size;
freeMem = freeMem-(size+8);
printf("free Mem : %d\n",freeMem);
return (int *)p->start;
}
}
p = (chunk *)p->end;
}
}
else{
printf("no space...!\n");
return 0;
}
}
void MyFree(void * p){
chunk *ptr = (chunk *)p;
ptr--;
freeMem=freeMem+(ptr->end - ptr->start)+sizeof(chunk);
if(ptr->start != 0){
printf("\nfreed Memory : %d\t",ptr->end - ptr->start);
ptr->start = 0;
}
else{
printf("\nno Such memory allocated!!!!!\n");
}
}