Ruby on Rails partials

Question

Can anyone help me out with the following? I have a partial view named _menu.html.erb inside a shared folder in views folder. I am trying to render this view inside my pages like so

<%= render "shared/menu" %>

But i am getting the following error.

Missing partial shared/_menu with {:locale=>[:en], :formats=>[:html], :variants=>[], :handlers=>[:erb, :builder, :raw, :ruby, :coffee, :jbuilder]}

What am I doing wrong?

Thanks!

Is your partial located at `app/views/shared/_menu.html.erb`? // Nevermind, stupid me. You already gave that answer in your question. — Philipp Meissner, Nov 06 '15 at 10:17
try to replace your line with this <%= render :partial => "/shared/menu" %> — Pooja Mokariya, Nov 06 '15 at 10:17
Thanks mokariya2 thats worked. But why? Is there any difference between render partial and just render? — T Karropoulos, Nov 06 '15 at 10:21
`render` can also take a full template as argument. You can, of course, specify whether it's a `partial`, what `layout` to use and other stuff. Do you by any chance have another file called `menu.html.erb` within the same folder? That might've caused the issue. — Philipp Meissner, Nov 06 '15 at 10:23
@TKarropoulos read this hope it will help you http://stackoverflow.com/questions/16822775/difference-between-render-and-render-partial-and-yield?lq=1 — Pooja Mokariya, Nov 06 '15 at 10:30
No I did not have any file called menu.html.erb. Anyway thanks for your help! Have a nice day! — T Karropoulos, Nov 06 '15 at 10:31

score 2 · Accepted Answer · answered Nov 06 '15 at 10:23

2

Put your menu.html.erb

here

app/views/shared/_menu.html.erb

and then render this with this line

<%= render :partial => "/shared/menu" %>

answered Nov 06 '15 at 10:23

Pooja Mokariya

1,970
5
21
46

score 0 · Answer 2 · answered Nov 06 '15 at 10:27

If you use just "render" with an argument, it's excpecting an ActiveRecord object, and will look for the "show" partial of this object, like this :

<%= render @user %> #this will render the "user/show" partial for @user

You can render a classical partial like this (without locals if you don't need any arguments) :

<%= render partial: "shared/menu", locals: {my_arg: my_val} %>

Ruby on Rails partials

2 Answers2