Python Regex extract string from line

Question

I am programming in Python 3.4. I am reading lines in different files and when I get to the line containing a specific string I want extract only the path string from that line. Example:

line in file is:

TEST_CASE_CHECK = require("TestCases/AOL/TU_Extract_Log_Details")

I search for: require("TestCases

I want extract only: TestCases/AOL/TU_Extract_Log_Details

I know this can be done with regex but I could not figure out how to do it.

Have a look at [*Extract a string between double quotes*](http://stackoverflow.com/questions/22735440/extract-a-string-between-double-quotes), might work for you, too. — Wiktor Stribiżew, Nov 06 '15 at 13:20

score 0 · Answer 1 · answered Nov 06 '15 at 13:21

0

I don't know what the rest of your lines look like but this should work

import re

s = 'TEST_CASE_CHECK = require("TestCases/AOL/TU_Extract_Log_Details")'

mat = re.search(r'(TestCases.*)"',s)
if mat:
    print(mat.group(1))

TestCases/AOL/TU_Extract_Log_Details

answered Nov 06 '15 at 13:21

SirParselot

2,640
2
20
31

Thank you very much! It worked. – marius alex Nov 06 '15 at 13:27
@mariusalex Don't forget to click the green check if this is your desired solution. – SirParselot Nov 06 '15 at 13:28

score 0 · Answer 2 · answered Nov 06 '15 at 13:23

0

Is it what you are looking for?

import re
p = re.compile(ur'require\("(TestCases[^"]*)')
test_str = u"TEST_CASE_CHECK = require(\"TestCases/AOL/TU_Extract_Log_Details\")"

re.findall(p, test_str)

https://regex101.com/r/zJ0sM3/1

answered Nov 06 '15 at 13:23

Doro

755
8
25

score 0 · Answer 3 · answered Nov 06 '15 at 13:23

0

import re

line = 'TEST_CASE_CHECK = require("TestCases/AOL/TU_Extract_Log_Details")'

result = re.match(r'.*require.+"([^"]*)".*', line)

print result.groups()[0] # prints "TestCases/AOL/TU_Extract_Log_Details"

answered Nov 06 '15 at 13:23

Robert

33,429
8
90
94

Python Regex extract string from line

3 Answers3