how to open a custom layout when menu item is pressed

Question

I have created a layout file which needs to displayed when a menu item is pressed.

   public boolean onOptionItemSelected(MenuItem item){
    switch (item.getItemId()) {
              ....
       case R.id.help:
           return true;
             ......
    }
}

the help item menu should display the layout.xml file.

Is it an activity or a dialog? – K Neeraj Lal Nov 07 '15 at 03:40 — K Neeraj Lal, Nov 07 '15 at 03:40
provide proper discription – Vishal Patel Nov 07 '15 at 07:28 — Vishal Patel, Nov 07 '15 at 07:28

score 1 · Accepted Answer · edited May 23 '17 at 11:51

1

You can use the layout in a new Activity. You can use Intent to invoke this new Activity,

Intent intent = new Intent(CurrentActivity.this, YourNewActivity.class);
startActivity(intent);

Or you can write a custom dialog to inflate the layout,

Android Custom Dialog Example

How to create a Custom Dialog box in android?

edited May 23 '17 at 11:51

Community

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answered Nov 07 '15 at 03:44

K Neeraj Lal

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but can it be launched when the menu item is clicked – Akshay komarla Nov 07 '15 at 03:55

how to open a custom layout when menu item is pressed

1 Answers1