I am using cygwin to compile my program. The command I use is g++ -std=c++11 -W -Wall -pedantic a1.cpp
I want to execute a part of code if debug mode is defined and another part if not.
My question is, what is that command to compile in debug mode and what should I put inside my code for the if/else execution?
You could add a command line option define like -DDEBUGMODE to your debug builds.
In your code you could decide what to do depending on DEBUGMODE being defined or not.
#ifdef DEBUGMODE
//DEBUG code
#else
//RELEASE code
#endif
I would also recommend to read _DEBUG vs NDEBUG and Where does the -DNDEBUG normally come from?
1- First debugging enable/disable method is to add -D to your completion command, like this:
gcc -D DEBUG <prog.c>
2- Second: To enable debugging define the MACRO that is replaced with a debugging statement like this:
#define DEBUG(fmt, ...) fprintf(stderr, fmt,__VA_ARGS__);
To disable debugging define The MACRO to be replaced with nothing like this:
#define DEBUG(fmt, ...)
Example ready to be debugged :
#include <stdio.h>
#include <stdlib.h>
int addNums(int a, int b)
{
DEBUG ("add the numbers: %d and %d\n", a,b)
return a+b;
}
int main(int argc, char *argv[])
{
int arg1 =0, arg2 = 0 ;
if (argc > 1)
arg1 = atoi(argv[1]);
DEBUG ("The first argument is : %d\n", arg1)
if (argc == 3)
arg2 = atoi(argv[2]);
DEBUG ("The second argument is : %d\n", arg2)
printf("The sum of the numbers is %d\n", addNums(arg1,arg2) );
return (0);
}
