Defining an array of array in php

Question

I have defined an array in php like this

<?php

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

echo $Type[0];


?>

When i am trying to print, it says "Err:Cannot convert array into string" Is this way of declaring is correct?? If not,can you share your views.

you should always using print_r when your dealing with arrays — saurabh kamble, Nov 07 '15 at 12:54
Var_dump gives similar if not better results http://stackoverflow.com/questions/3406171/php-var-dump-vs-print-r — mrhn, Nov 07 '15 at 23:29

score 2 · Answer 1 · answered Nov 07 '15 at 11:40

2

It can't echo $Type[0] because it is an array. Array's can be printed using print_r().

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

print_r($Type[0]);

answered Nov 07 '15 at 11:40

Thaillie

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Thanks for sharing. @Thaillie – Rasik Suhail Nov 07 '15 at 11:45

score 0 · Accepted Answer · answered Nov 07 '15 at 11:42

If you want to debug you variables, to see what they look like, a simple solution could be to var_dump em.

var_dump($Type[0]);

But you are not doing anything wrong, except you can't echo an array this is an legal print statement as an example.

echo $Type[0][0];

score 0 · Answer 3 · answered Nov 07 '15 at 11:43

try it and see result -

<?php

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

var_dump($Type);


?>

Defining an array of array in php

3 Answers3