I want to pass a variable by parameter and then allocated a memory region using malloc to that parameter. Actually, I know how to do that, but I was wondering why this function does not work as I expected:
void temp1(int *a) {
int *b = (int*) malloc(sizeof(int));
a = b; // a receives the pointer from b, only while it's in temp1 function;
}
while this function works:
void temp2(int **a) {
int *b = (int*) malloc(sizeof(int));
*a = b;
}
when calling this way from main:
int main()
int *t1 = NULL;
temp1(t1); // but after exiting the temp1 function the t1 value is still NULL
int *t2;
temp2(&t2); // this works
return 0;
}
So, what I'm missing in the function temp1 that avoids it to work? Is it because in function temp1 I'm trying to change the content of the parameter int *a? I mean, when I do a = b; in temp1 the a holds only a copy of the address that I wanted to assign to t1?
