I have next entity configuration:
public class OfficesContext : DbContext
{
public DbSet<Office> Offices { get; set; }
public DbSet<Expense> Expenses { get; set; }
public DbSet<ExpenseLog> ExpenseLogs { get; set; }
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
modelBuilder.Entity<Office>()
.Property(o => o.OfficeId)
.HasDatabaseGeneratedOption(DatabaseGeneratedOption.None);
modelBuilder.Entity<Expense>()
.Property(o => o.ExpenseId)
.HasDatabaseGeneratedOption(DatabaseGeneratedOption.None);
modelBuilder.Entity<Office>()
.HasMany(o => o.Expenses)
.WithMany()
.Map(mc =>
{
mc.ToTable("ExpenseLogs");
mc.MapLeftKey("ExpenseId");
mc.MapRightKey("OfficeId");
});
}
}
public class Office
{
public Office()
{
ExpenseLogs = new HashSet<ExpenseLog>();
Expenses = new HashSet<Expense>();
}
public int OfficeId { get; set; }
public string Name { get; set; }
public ICollection<ExpenseLog> ExpenseLogs { get; private set; }
public ICollection<Expense> Expenses { get; private set; }
}
public class Expense
{
public Expense()
{
ExpenseLogs = new HashSet<ExpenseLog>();
Offices = new HashSet<Office>();
}
public int ExpenseId { get; set; }
public string Name { get; set; }
public ICollection<ExpenseLog> ExpenseLogs { get; private set; }
public ICollection<Office> Offices { get; private set; }
}
public class ExpenseLog
{
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
public int ExpenseLogId { get; set; }
public int OfficeId { get; set; }
public Office Office { get; set; }
public int ExpenseId { get; set; }
public Expense Expense { get; set; }
public DateTime InputDate { get; set; }
public decimal Amoun { get; set; }
public string Description { get; set; }
}
But it creates two tables for expences logs ExpenseLogs and ExpenseLogs1. ExpenseLogs has only foreign keys ExpenseId and OfficeId. ExpenseLogs1 has same fields as in class ExpenseLog. I also tried to use next mappings but it doesnt helped:
modelBuilder.Entity<ExpenseLog>().HasRequired(e => e.Office);
modelBuilder.Entity<ExpenseLog>().HasRequired(e => e.Expense);