I use sizeof() method to get the memory size of char variable. i.e.,I write such a code in Xcode:
char a = '1';
size_t size = sizeof(a);
I find the size is 1.So what is this character's encoding type? UTF-8 or another?
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1maybe this helps: http://stackoverflow.com/questions/3996026/what-is-the-default-encoding-for-c-strings – albertamg Nov 13 '15 at 15:16
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3The `sizeof(char)` is _always_ 1, by definition, in C. – chux - Reinstate Monica Nov 13 '15 at 15:30
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OT: `sizeof` isn't a method or alike, but an operator. – alk Nov 13 '15 at 16:15
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You'd have to know this before using the character, just as you are expected to know the encoding of a string before you can interpret it correctly.
You cannot determine the encoding without prior knowledge.
trojanfoe
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The sizeof method is not enough to determine what the encoding of a character is.
In general, you must be told what encoding is being used before being able to interpret characters.
As stated in a comment, look here for some information on C string encoding: What is the default encoding for C strings?
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No, I can't understand. i.e.,I write this code in C, char a = '1'; is the encoding is not certained? – huixing Nov 13 '15 at 15:06
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For some character literals the C Standard defines a fixed value (the digits if I remembers correctly) for others (letters) the C Standard leaves it to the implementation which char-set/encoding to use.
alk
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