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I saw on some online sources that they allocate a block of memory for an array of n integers as follows: 

memory = (int*) malloc(n*sizeof(int))

What's the role of (int*) here?

BLUEPIXY
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Jack Shi
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    Nothing, it's a mistake that appeared in a popular 1970s book and people have been copying it ever since without thinking about it. `memory = malloc(n * sizeof(int));` or `memory = malloc(n * sizeof *memory);` is correct. The latter has the advantage that you cannot accidentally name the wrong type and thereby allocate the wrong amount of memory. – M.M Nov 14 '15 at 06:38

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