How can I force PHP's json_encode integer values to be encoded as String?

Question

I'm using PHP v5.6.

As i read that php json_encode function is automatically converting int to string. But not in my case. Json_encode is still return it to int not string.

Like example:

json_encode(['code' => 200, 'results' => [id=> 1]]);

my expected results is all become a string. but what i get is

{"code":200,"results":{"id": 1}}

Expected output:

{"code":"200","results":{"id": "1"}}

How can i change all the result become string without using "" for every value?.

NB: results array is based on query.

score 6 · Accepted Answer · edited May 23 '17 at 10:33

6

In the link posted by Thomas in comments, one user suggests that you do this:

$data = json_encode(array_map('strval', $data));

This might not be the most efficient in terms of performace though, since every entry on the array will pass through the strval function.

edited May 23 '17 at 10:33

Community

1
1

answered Nov 15 '15 at 16:57

Marcos Dimitrio

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5
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yes. at last i got a way to use array_map and array walk properly. so it can change all the int to string automatically. Thanks for the heads up! – ssuhat Nov 16 '15 at 02:02
This is only a suitable technique if the input array is guaranteed to be one-dimensional. Otherwise, there will be problems https://3v4l.org/GcIma. – mickmackusa Apr 09 '21 at 15:12
@Marcos Dimitrio thanks for your answer its works like charm. – Shamsi786 Sep 08 '21 at 12:43

score 0 · Answer 2 · answered Nov 14 '15 at 07:22

0

json_encode(['code' => 200, 'results' => [id=> strval(1)]]);

With strval() php will return

The string value of var.

answered Nov 14 '15 at 07:22

online Thomas

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yes. i use strval. but its from query result. if i use strval it will be a lot of value to use strval() – ssuhat Nov 14 '15 at 07:24
@sstarlight are you affraid it might influence performance, what is exactly the problem with ` it will be a lot of value to use strval() `? – online Thomas Nov 14 '15 at 07:28
I mean. if inside results. i have 50 value. and it need to convert to strval. It will be not efficient enough. – ssuhat Nov 14 '15 at 07:32
Yes, this would be rather painstaking to manually call `strval()` on 50 columns in a result set. – mickmackusa Apr 09 '21 at 15:14

mickmackusa · Answer 3 · 2021-04-09T15:15:06.377

To ensure that all numeric "leaf nodes" of a potentially multi-dimensional array are cast as strings, call array_walk_recursive() and make conditional changes to each value type. By checking if the value "is numeric", you prevent values like null and booleans from being cast as strings.

Code: (Demo)

$array = [
    'code' => 200,
    'results' => [
        'id' => 1
    ],
    'a' => [
        [
            'b' => [
                4,
                null,
                false
            ]
        ]
    ]
];

array_walk_recursive(
    $array,
    function(&$v) {
        if (is_numeric($v)) {
            $v = strval($v);
        }
    }
);
echo json_encode($array);

Output:

{"code":"200","results":{"id":"1"},"a":[{"b":["4",null,false]}]}

How can I force PHP's json_encode integer values to be encoded as String?

3 Answers3

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