JFrame draw image at x = 0 and y = 0 right next to border

Asked Nov 15 '15 at 14:24

Active Nov 15 '15 at 14:24

Viewed 30 times

This is my code:

public class Test extends JFrame {

static BufferedImage s;

public static void main(String[] args) throws IOException {
    Test t = new Test();
    s = ImageIO.read(new File("test.png"));
    t.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    t.setSize(600, 600);
    t.setVisible(true);
}

@Override
public void paint(Graphics g) {
    super.paint(g);
    g.drawImage(s, 0, 0, 32, 32, this);
}}

Basically if I draw my image at those coordinates it'll draw part of my image under the JFrame border (both the left border and the top border that has the JFrame title) so the only way to get around it would be by calculating the size of both borders.

Is the only way to draw my image next to both borders to calculate their sizes? If yes then what if I decide to run this code on Linux, doesn't it have different sizes for its borders?

asked Nov 15 '15 at 14:24

user250327

2

Draw it onto a `JPanel` instead. (overriding `paintComponent(Graphics g)`); – Lukas Rotter Nov 15 '15 at 14:25
2

Read the graphics tutorials as they'll tell you exactly what @LuxxMiner mentions above. You should never draw directly within a JFrame. Please also see [this link](http://stackoverflow.com/questions/24026743/why-not-to-draw-directly-inside-jframe). – Hovercraft Full Of Eels Nov 15 '15 at 14:26
Ohh yes I completly forgot about it. Thank you guys. – user250327 Nov 15 '15 at 14:30

JFrame draw image at x = 0 and y = 0 right next to border

0 Answers0