how to sort tuple value from list in python

Question

I have list of tuple values. I need to sort value by id from the tuple list. Can anyone help me to do this.

  l = [('abc','23'),('ghi','11'),('sugan','12'),('shankar','10')]

I need a output like this.

  l = [('shankar','10'),('ghi','11'),('sugan','12'),('abc','23')]

and also if i need to sort like this means

  l =  [('abc', '23'),('sugan', '12'),('ghi', '11'),('shankar', '10')]

There is a similar answer here (like Avinash Raj gave it): [https://stackoverflow.com/questions/3121979/how-to-sort-list-tuple-of-lists-tuples](https://stackoverflow.com/questions/3121979/how-to-sort-list-tuple-of-lists-tuples) — rocksteady, Nov 16 '15 at 08:48

score 6 · Accepted Answer · answered Nov 16 '15 at 07:49

6

You may pass key param to sorted function.

>>> l = [('abc','23'),('ghi','11'),('sugan','12'),('shankar','10')]
>>> sorted(l, key=lambda x: int(x[1]))
[('shankar', '10'), ('ghi', '11'), ('sugan', '12'), ('abc', '23')]
>>>

answered Nov 16 '15 at 07:49

Avinash Raj

172,303
28
230
274

if i need to sort like this means [('abc', '23'),('sugan', '12'),('ghi', '11'),('shankar', '10')] – Python Team Nov 16 '15 at 08:54
if you want it in descending order just use `sorted(l, key=lambda x: int(x[1]), reverse=True)` – Nhor Nov 16 '15 at 08:58

score 0 · Answer 2 · answered Nov 16 '15 at 07:56

0

Try this to sort

sorted(yourList, key=lambda tupVal: float(tupVal[1]))

answered Nov 16 '15 at 07:56

Mangu Singh Rajpurohit

10,806
4
68
97

how to sort tuple value from list in python

2 Answers2