how 2 repeat a part of a regex and the nthe rest of the string

Question

I want to match this string domain1.com,domain2.com,domain3.com###someString

So I need a regex that matches all 3 domains and the #someString. I've found this pattern to validate url's, so I thought I could use that regex to filter domains as well.

/^(http|https):\/\/(([a-zA-Z0-9$\-_.+!*'(),;:&=]|%[0-9a-fA-F]{2})+@)?(((25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])(\.(25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])){3})|localhost|([a-zA-Z0-9\-\u00C0-\u017F]+\.)+([a-zA-Z]{2,}))(:[0-9]+)?(\/(([a-zA-Z0-9$\-_.+!*'(),;:@&=]|%[0-9a-fA-F]{2})*(\/([a-zA-Z0-9$\-_.+!*'(),;:@&=]|%[0-9a-fA-F]{2})*)*)?(\?([a-zA-Z0-9$\-_.+!*'(),;:@&=\/?]|%[0-9a-fA-F]{2})*)?(\#([a-zA-Z0-9$\-_.+!*'(),;:@&=\/?]|%[0-9a-fA-F]{2})*)?)?$/

I changed it to this so http(s):// is not required, there will never be a protocol before a domain name:

/^(([a-zA-Z0-9$\-_.+!*'(),;:&=]|%[0-9a-fA-F]{2})+@)?(((25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])(\.(25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])){3})|localhost|([a-zA-Z0-9\-\u00C0-\u017F]+\.)+([a-zA-Z]{2,}))(:[0-9]+)?(\/(([a-zA-Z0-9$\-_.+!*'(),;:@&=]|%[0-9a-fA-F]{2})*(\/([a-zA-Z0-9$\-_.+!*'(),;:@&=]|%[0-9a-fA-F]{2})*)*)?(\?([a-zA-Z0-9$\-_.+!*'(),;:@&=\/?]|%[0-9a-fA-F]{2})*)?(\#([a-zA-Z0-9$\-_.+!*'(),;:@&=\/?]|%[0-9a-fA-F]{2})*)?)?$/

But ofcourse that would only match one domain and nothing more. Unfortunately I don't have enough knowlegde to repeat this pattern so it would match my string. I'd like to have this output:

match1:
    domain1.com
    domain2.com
    domain3.com

match2:
     #someString

I use Javascript only.

https will never be in the domain, that's why I removed it. – Nov 16 '15 at 10:14 — , Nov 16 '15 at 10:14
Like [this](https://regex101.com/r/dV4iR6/1), perhaps. – Wiktor Stribiżew Nov 16 '15 at 10:16 — Wiktor Stribiżew, Nov 16 '15 at 10:16
Thanks, could you explain what you changed – Nov 16 '15 at 10:17 — , Nov 16 '15 at 10:17
@FIA2008: I added the necessary explanations. – Wiktor Stribiżew Nov 16 '15 at 10:44 — Wiktor Stribiżew, Nov 16 '15 at 10:44

Wiktor Stribiżew · Accepted Answer · 2015-11-16T10:43:14.963

You can remove the anchors ^/$ so that the match could be found inside a larger string and add a subpattern to match # followed with 1 or more alphanumerics #\w+:

(([a-zA-Z0-9$\-_.+!*'(),;:&=]|%[0-9a-fA-F]{2})+@)?(((25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])(\.(25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])){3})|localhost|([a-zA-Z0-9\-\u00C0-\u017F]+\.)+([a-zA-Z]{2,}))(:[0-9]+)?(\/(([a-zA-Z0-9$\-_.+!*'(),;:@&=]|%[0-9a-fA-F]{2})*(\/([a-zA-Z0-9$\-_.+!*'(),;:@&=]|%[0-9a-fA-F]{2})*)*)?(\?([a-zA-Z0-9$\-_.+!*'(),;:@&=\/?]|%[0-9a-fA-F]{2})*)?(\#([a-zA-Z0-9$\-_.+!*'(),;:@&=\/?]|%[0-9a-fA-F]{2})*)?)?|#\w+

See regex demo

JS snippet:

var re = /(([a-zA-Z0-9$\-_.+!*'(),;:&=]|%[0-9a-fA-F]{2})+@)?(((25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])(\.(25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])){3})|localhost|([a-zA-Z0-9\-\u00C0-\u017F]+\.)+([a-zA-Z]{2,}))(:[0-9]+)?(\/(([a-zA-Z0-9$\-_.+!*'(),;:@&=]|%[0-9a-fA-F]{2})*(\/([a-zA-Z0-9$\-_.+!*'(),;:@&=]|%[0-9a-fA-F]{2})*)*)?(\?([a-zA-Z0-9$\-_.+!*'(),;:@&=\/?]|%[0-9a-fA-F]{2})*)?(\#([a-zA-Z0-9$\-_.+!*'(),;:@&=\/?]|%[0-9a-fA-F]{2})*)?)?|#\w+/g; 
var str = 'domain1.com,domain2.com,domain3.com###someString';
var res = str.match(re)
document.getElementById("r").innerHTML = JSON.stringify(res);

<div id="r"/>

Glad it worked for you. Please also consider upvoting if my answer proved helpful to you (see [How to upvote on Stack Overflow?](http://meta.stackexchange.com/questions/173399/how-to-upvote-on-stack-overflow)). — Wiktor Stribiżew, Nov 16 '15 at 10:50

how 2 repeat a part of a regex and the nthe rest of the string

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