Reverse numbers

Question

I'm just starting out in programming. I am trying to develop a program that collects any amount of integer numbers and reverses the order in which they were entered. Say 1 6 8 9 4 9 becomes 9 4 9 8 6 1 This is what I did:

    System.out.println("Enter ten  numbers:");
    int[] n = new int[10];
    for (int i =0; i<n.length; i++)
    n[i] = input.nextInt();

 for(int i =0; i<n.length-1; i++)
     for (int j= n.length-1; j>0; j--){
    int temp = n[i];
    n[i] = n[j];
    n[j] = ;
  }
}

score 1 · Answer 1 · answered Nov 17 '15 at 20:43

1

If you want to swap-reverse all numbers you can do this:

for(int i = 0; i < array.length / 2; i++)
{
    int temp = array[i];
    array[i] = array[array.length - i - 1];
    array[array.length - i - 1] = temp;
}

answered Nov 17 '15 at 20:43

Vollmilchbb

481
6
20

There's a tiny flaw with your code. What happens when the length of the array is odd? :) – Matthew Chrobak Nov 17 '15 at 20:45
oh in that case he still can cast to `double`, but you're right. – Vollmilchbb Nov 17 '15 at 20:47
In this case, yes. But in his question, he states "that collects any amount of integer numbers". – Matthew Chrobak Nov 17 '15 at 20:48

score 0 · Accepted Answer · answered Nov 17 '15 at 20:54

0

If all you want to do is print them out in the reverse order, why reverse the array? Just print them:

   System.out.println("Enter ten  numbers:");
    int[] n = new int[10];
    for (int i =0; i<n.length; i++) {
       n[i] = input.nextInt();
    }
    for ( int i=n.length-1; i >=  0; i-- ) {
       System.out.println( n[i] );
    }

answered Nov 17 '15 at 20:54

FredK

4,094
1
9
11

You are right on the printing part but is it possible to collect the numbers going into the println statement back into the original array? If so will that reverse the original array? – Malvins Chelsi Nov 17 '15 at 21:25

Reverse numbers

2 Answers2