Int in base 2 to binary string python

Question

So I have this operation in python x = int(v,base=2) which takes vas a Binary String. What would be the inverse operation to that? For example, given 1101000110111111011001100001 it would return 219936353, so I want to get this binary string from the 219936353 number. Thanks

score 3 · Accepted Answer · edited Jul 20 '18 at 12:56

3

Try out the bin() function.

bin(yourNumber)[2:]

will give you string containing bits for your number.

edited Jul 20 '18 at 12:56

ifloop

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answered Nov 18 '15 at 09:06

Mangu Singh Rajpurohit

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thanks! If I operate with this string the `0b` from the start won't interfere with the operation, right? – lpares12 Nov 18 '15 at 09:18
What exact operation, do you want to perform ? – Mangu Singh Rajpurohit Nov 18 '15 at 09:18
@deuseux12 You can use `print bin(219936353)[2:].zfill(8)` to remove that `0b`. – Avión Nov 18 '15 at 09:20
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okey. That binary string is the conversion from the word "hola" to binary. So I would have to convert the binary string to the word. If it gives any problem I'll use Borja solution to take the `0b` out. Thanks – lpares12 Nov 18 '15 at 09:22
@deuseux12, This doesn't work: `int(bin(1), 10)`. See my answer for the first correct solution: `int('{:b}'.format(1), 10)` => `1`. – 7stud Nov 18 '15 at 09:33
@7stud why would interpreting the binary representation as if it was a decimal representation be a useful thing to do? – jonrsharpe Nov 18 '15 at 19:06
@johnsharpe, Huh? My answer was the only answer that did what the op asked. If you don't understand why the op wants to round trip a decimal number to a binary string and back to a decimal number, then why don't you ask the op? – 7stud Nov 18 '15 at 20:00
@7stud did you read the question? That's not what they want... – jonrsharpe Nov 18 '15 at 23:53
@jonrsharpe, The op said, *I want to get this binary string from the 219936353 number*, where ***this*** refers to `1101000110111111011001100001`. Okay??! – 7stud Nov 19 '15 at 04:09

7stud · Answer 2 · 2015-11-18T09:39:01.133

num = 219936353
print("{:b}".format(num))

--output:--
1101000110111111011001100001

The other solutions are all wrong:

num = 1
string = bin(1)
result = int(string, 10)
print(result)

--output:--
Traceback (most recent call last):
  File "1.py", line 4, in <module>
    result = int(string, 10)
ValueError: invalid literal for int() with base 10: '0b1'

You would have to do this:

num = 1
string = bin(1)
result = int(string[2:], 10)
print(result)  #=> 1

score 0 · Answer 3 · answered Nov 18 '15 at 09:09

0

>>> bin(219936353)
'0b1101000110111111011001100001'

answered Nov 18 '15 at 09:09

11thdimension

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Mind to [explain your solution](http://stackoverflow.com/help/how-to-answer) a bit? – Markus W Mahlberg Nov 18 '15 at 09:27

Int in base 2 to binary string python

3 Answers3